Delete Account

Hi everyone,

i can’t change my email in my roboflow account.
So I create a new one and migrate my models.

How I can delete a account from app.roboflow.com ?

Regards

First, invite yourself to any workspaces you need access to, and accept the invitation with your new account: https://docs.roboflow.com/roboflow-workspaces/adding-team-members-to-a-workspace

Next, please reply to me here when you have completed that step, and we will process the deletion and confirm it for you.

Hello Mohamed,

i have a backup of my dataset. The account can be deleted.

Regards
Manuel

Hello Mohamed,

the account already exist. When can I expect the deletion?

Regards
Manuel

@Elmar Following up to confirm your request has been processed. The account should be deleted.

Hello Mohamed,
thanks for your support.

I will give you a litte feedback about my reasons for the deletion.
I was registered with my github-account. Unfortunately roboflow leaked
my private Email-Adress to the public with my projects

I’m wondering about many Spammails to this Address, which I have never
used in public. It is perfectly acceptable to make my project-files
public in the free-plan, but leaking my Email and link my Project
to my Full Name in public is an absolute noGo for me.
About that I’m not being able to use roboflow furthermore.

Best Regards
Manuel Fleder

@Elmar Hi Manuel, I do understand the hesitation to continue usage after experiencing that. My apologies for the experience.

We’ve relayed your feedback to the team on this.

One question I have, to help us get to the bottom of the email address appearing - when you did sign-in with GitHub, were you prompted to fill in a First and/or Last Name during sign-up, or was that part of the sign-up flow bypassed?

Note - I edited your reply to remove the image, so others don’t see your email. I was sure to save it first to send internally.

I want to delete my account too, please help me with the steps. I don’t have any workspace to join. Please delete my account, I don’t use it anymore.